33=x^2-2x

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Solution for 33=x^2-2x equation:



33=x^2-2x
We move all terms to the left:
33-(x^2-2x)=0
We get rid of parentheses
-x^2+2x+33=0
We add all the numbers together, and all the variables
-1x^2+2x+33=0
a = -1; b = 2; c = +33;
Δ = b2-4ac
Δ = 22-4·(-1)·33
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{34}}{2*-1}=\frac{-2-2\sqrt{34}}{-2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{34}}{2*-1}=\frac{-2+2\sqrt{34}}{-2} $

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